D.S. Morgan Mathematics

dsmorgan.com

Structure of the Galilean group

Theorem 5.4 (Structure of the Galilean group). Every Galilean transformation \(g\) of \(\R \times \R ^3\) can be written uniquely as

\[ g = g_1 \circ g_2 \circ g_3, \]

where \(g_1\) is a uniform motion, \(g_2\) a translation and \(g_3\) a rotation (Exercise 5.3).

Source: [1, ch. 1]

Proof. A Galilean transformation is affine, so \(g(t, \mathbf x) = L(t, \mathbf x) + (s, \mathbf s)\) for a linear map \(L\) and a fixed \((s, \mathbf s) \in \R \times \R ^3\).

Time. \(g\) preserves time intervals, so the time component of \(L(\tau , \boldsymbol \xi )\) is \(\tau \).

Space. Hence \(L\) sends a simultaneous displacement \((0, \boldsymbol \xi )\) to a simultaneous displacement \((0, G\boldsymbol \xi )\) for some linear \(G : \R ^3 \to \R ^3\). Distances between simultaneous events are preserved, so \(\abs {G\boldsymbol \xi } = \abs {\boldsymbol \xi }\), and \(G\) is orthogonal.

Velocity. Write \(L(1, \mathbf 0) = (1, \mathbf v)\). By linearity \(L(\tau , \boldsymbol \xi ) = (\tau , \mathbf v\tau + G\boldsymbol \xi )\), so

\[ g(t, \mathbf x) = (t + s,\; G\mathbf x + \mathbf v t + \mathbf s). \]

Factorisation. For \(g_1(t, \mathbf x) = (t, \mathbf x + \mathbf v t)\), \(g_2(t, \mathbf x) = (t + s, \mathbf x + \mathbf u)\) and \(g_3(t, \mathbf x) = (t, G\mathbf x)\),

\[ g_1 g_2 g_3 (t, \mathbf x) = \bigl (t + s,\; G\mathbf x + \mathbf u + \mathbf v(t + s)\bigr ). \]

This equals \(g\) exactly when \(\mathbf u = \mathbf s - \mathbf v s\).

Uniqueness. The composite determines \(s\) (its time shift), \(G\) (its action on \(\mathbf x\)), \(\mathbf v\) (its coefficient of \(t\)) and then \(\mathbf u\). So two factorisations of the same \(g\) coincide.